Question

To determine the height of a steep cliff an experimenter stations a sensor on the top of the cliff then fires a pellet vertically upward with an initial velocity of 80 m/s . the sensor reports that the pellet reached a maximum height 3 meters above the edge of the cliff. how high is the cliff?​

a. 77 m
b. 237 m
c. 317 m
d. 637 m
e. 797 m​

Answer 1

c. 317 m

Step-by-step explanation:

Vertical Launch Upwards

It occurs when an object is launched vertically up without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

`\displaystyle h_m=(v_o^2)/(2g)`

We'll assume the acceleration of gravity as
`g=10\ m/s^2`.The pellet is vertically upward launched with vo=80 m/s. The maximum height is:

`\displaystyle h_m=(80^2)/(2*10)=320`

`h_m = 320\ m`

That height is 3 meters above the edge of the cliff, thus the cliff is 320-3=317 m hight

c. 317 m