Answer:
![\boxed {\boxed {\sf x=2}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/810ppupuer15l2emm6ke6ja4yesrbm1jl7.png)
Explanation:
We know that:
![f(x)=4x+2 \\f(x)= 10](https://img.qammunity.org/2021/formulas/mathematics/high-school/vdg1y98zmv25qntrfla4qzb3rzyumzb7e7.png)
Both 4x+2 and 10 are equal to f(x). We can use substitution and set 4x+2 and 10 equal to each other.
![4x+2=10](https://img.qammunity.org/2021/formulas/mathematics/high-school/3mywyyv6vpv6tjz2jnwvsu6nhhp29w0o2o.png)
Now, solve for x. Perform the inverse operations to isolate x on one side of the equation.
2 is being added to 4x. The inverse of addition is subtraction. Subtract 2 from both sides of the equation.
![4x+2-2=10-2](https://img.qammunity.org/2021/formulas/mathematics/high-school/xvwy5nxwaf7g9t3odn8smt6tto0um3njee.png)
![4x=10-2 \\](https://img.qammunity.org/2021/formulas/mathematics/high-school/wcr6fl0io5tou32j26sin2dlh9z64647mp.png)
![4x=8](https://img.qammunity.org/2021/formulas/mathematics/high-school/kz9e6lrgtwequoybu6dusu3mdx8dhegp2d.png)
x is being multiplied by 4. The inverse of multiplication is division. Divide both sides of the equation by 4.
![(4x)/(4) =(8)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/i0ikrtrhmpq637u5oo4fgwp9ragjcvxgjy.png)
![x=(8)/(4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/4vkntr43uyfc4ji0uy37touuy2nw76rlvk.png)
![x=2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/l44oth01qqbnuop6qxtvmqlzuv7kvr7xrb.png)
For the function f(x)= 4x+2, when f(x)=20, x=2