Question

What mass of water would increase in temperature from 45.0℃ to 98.0℃ after absorbing 6830 J of energy?

Answer 1

Mass of water : 30.83 g

Further explanation

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

• ∆T = temperature difference

`\tt \Delta T=T_f(final)-T_i(initial)\\\\\Delta T=98-45=53^oC`

• mass of water

`\tt m=(Q)/(c* \Delta T )\\\\m=(6830)/(4.18* 53)\\\\m=30.83~g`