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The parametric equations x = square root t, y= 3t - 4 for t in [ 0,4] define a plane curve

The parametric equations x = square root t, y= 3t - 4 for t in [ 0,4] define a plane-example-1
User Islingre
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2 Answers

1 vote

Final answer:

The student's question involves parametric equations defining a plane curve, and not a quadratic equation. However, if presented with a quadratic equation, the solution can be found using the quadratic formula.

Step-by-step explanation:

The parametric equations x = √(t), y = 3t - 4 define a plane curve for t in the interval [0,4]. This is a set of mathematical expressions used to describe a curve in a two-dimensional plane, where t acts as the parameter. It is not a quadratic equation, which typically has the form at² + bt + c = 0. However, should you encounter a quadratic equation, the solutions can be found using the quadratic formula which is given by -b ± √(b² - 4ac) / 2a. The quadratic formula helps to solve for the values of t when the quadratic equation is set to zero.

User Lassi
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3 votes

Answer:

a) We kindly invite you to read the explanation and check the image attached below for further details.

b) The rectangular equation is
y = 3\cdot x^(2)-4.

Step-by-step explanation:

a) Let
x = √(t) and
y = 3\cdot t -4 for
t\in[0,4]. We proceed to graph the expression with the help of a graphing tool. In this case, the tool Desmos is used and the result is presented below.

b) The rectangular equation for the curve is:


t = x^(2) (1)


y = 3\cdot t - 4 (2)

By applying (1) in (2), we get the following equation in rectangular form:


y = 3\cdot x^(2)-4

The parametric equations x = square root t, y= 3t - 4 for t in [ 0,4] define a plane-example-1
User Safeta
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