Question

Please answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Answer 1

`\pink{\sf Third \: side \: of \: the \: triangle = 45}`

Solution :

As, the given triangle is a right angled triangle,

Hence, We can use the Pythagoras' Theorem,

`\star\:{\boxed{\sf{\pink {H^(2) = B^(2) + P^(2)}}}}`

Here,

• H = Hypotenuse of triangle
• B = Base of triangle
• P = Perpendicular of triangle

In given triangle,

• Base = 24
• Hypotenuse = 51
• Perpendicular = ?

Now, by Pythagoras' theorem,

`\star\:{\boxed{\sf{\pink {H^(2) = B^(2) + P^(2)}}}}`

`\sf : \implies (51)^(2) = (24)^(2) + P^(2)`

`\sf : \implies 51 * 51 = 24 * 24 + P^(2)`

`\sf : \implies 2601 = 576 + P^(2)`

`\sf : \implies P^(2) = 2601 - 576`

`\sf : \implies P^(2) = 2025`

By squaring both sides :

`\sf \sqrt{P^(2)} = √(2025)`

`\sf : \implies P^(2) = √(2025)`

`\sf : \implies P^(2) = \sqrt{(45)^(2)}`

`\sf : \implies P^(2) = 45`

`\pink{\sf \therefore \: Third \: side \: of \: the \: triangle \: is \: 45}`

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