How many moles of NO2 form when 63.25 g N2O5 decompose? 2N₂O54NO₂ + O₂

Nazar Vynnytskyi asked Jul 18, 2023

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How many moles of NO2 form when
63.25 g N2O5 decompose?

2N₂O54NO₂ + O₂

Nazar Vynnytskyi asked Jul 18, 2023

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16 votes

Answer:

1.1713 moles

Step-by-step explanation:

RFM of N2O5=108

Moles of N2O5= mass/RFM= 63.25/108=0.5856 moles

Mole ratio of N2O5:NO2= 2:4

Therefore moles of NO2= 4/2*0.5856= 1.1713 moles

TheMook answered Jul 22, 2023

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