Question

Can someone please help me

Answer 1

Explanation:

the given function is f(x) = 8x² + 2x -6

f(0) = 8(0)² + 2(0) -6 = -6

f(2) = 8 (2)² + 2 (2) - 6 = 30

f(-2) = 8 (-2)² + 2 (-2) - 6 = 22

f (x+1) = 8(x+1)² + 2 (x+1) -6

= 8(x² +2x +1 ) + 2x -4

8x² + 16x +8 +2x -4 = 8x² + 18x + 4

f(-x) = 8(-x)² + 2 (-x) - 6

= 8x² -2x -6

Answer 2

-6, 14, -26, 10x -4, -8x + -2x - 6

Explanation:

So F(x) is setting that the values before the lines are equal to x and should be applied to the problem. Dont forget PEMDAS with these tho, they'll try to trick u like that.

So for the first one, f(0) you plug 0 where the x's are.

1.) 8(0)^2 +2(0) -6

0 + 0 - 6 = -6

2.) 8(2) +2(2) - 6

16+ 4-6= 20 - 6= 14

3.) 8(-2) + 2(-2) -6

-16 + -4 -6 = -26

On the ones where they leave the x there, you just have to leave the x. But don't forget distribution tho.

4.) 8(x+1) +2(x+1) -6

8x +8 + 2x + 2 -6

10x +10 -6 = 10x -4

5.) 8(-x) + 2(-x) -6

-8x + -2x -6