How many molecules are in 4.5 moles of Ca(OH),?

Question

asked Dec 9, 2021 76.1k views

2 Answers

Steve Perks · Answer 1 · 2021-12-14T02:31:53+0000

We will use dimensional analysis to solve this.

We will need to know Avogadro's number, which is 6.02 × 10²³.

4.5 mol ×
(6.02 * 10^(23) molecules)/(1 mol) = 2.71 × 10²⁴ molecules.

There are 2.71 × 10²⁴ molecules in 4.5 moles of Ca(OH).