Question

N204(0) + 2NO2(g)

Colorless Brown
Keq = 6.16 x 103
What is the predicted direction of change?

Answer 1

The system will shift toward the products

The system is at equilibrium

The system will shift toward the reactants

Step-by-step explanation:

This is correct on edg... Good Luck!!!!

Answer 2

setup 1 : to the right

setup 2 : equilibrium

setup 3 : to the left

Further explanation

The reaction quotient (Q) : determine a reaction has reached equilibrium

For reaction :

aA+bB⇔cC+dD

`\tt Q=(C]^c[D]^d)/([A]^a[B]^b)`

Comparing Q with K( the equilibrium constant) :

K is the product of ions in an equilibrium saturated state

Q is the product of the ion ions from the reacting substance

Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)

Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium

Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)

Keq = 6.16 x 10⁻³

Q for reaction N₂O₄(0) ⇒ 2NO₂(g)

`\tt Q=([NO_2]^2)/([N_2O_4])`

Setup 1 :

`\tt Q=(0.0064^2)/(0.098)=0.000418=4.18* 10^(-4)`

Q<K⇒The reaction moved to the right (products)

Setup 2 :

`\tt Q=(0.0304^2)/(0.15)=0.00616=6.16* 10^(-3)`

Q=K⇒the system at equilibrium

Setup 3 :

`\tt Q=(0.230^2)/(0.420)=0.126`

Q>K⇒The reaction moved to the left (reactants)