Question

ABC is translated left 3 units to form the image ∆A′B′C′.

What are the coordinates of the vertices of ∆A′B′C′ ?
A′ = ( , )

B′ = ( , )

C′ = ( , )

Answer 1

The coordinates of the vertices of ∆A'B'C' are:

A': (-2, 1)

B': (-1, 4)

C': (-2, 3)

Given: Triangle ABC with vertices A(1, 1), B(2, 4), and C(1, 3).

Transformation: Triangle ABC is translated left 3 units to form ∆A'B'C'.

Finding the coordinates of A'B'C':

Shifting the x-coordinates: Since the translation is 3 units left, we need to subtract 3 from the x-coordinate of each original vertex. This is because moving left corresponds to decreasing the x-value.

A'(1 - 3, 1) = (-2, 1)

B'(2 - 3, 4) = (-1, 4)

C'(1 - 3, 3) = (-2, 3)

Preserving the y-coordinates: The translation only affects the horizontal position, so the y-coordinates remain the same.

Answer 2

A = (-2 , -1) A’ = (-5 , -1)

B = (2 , -1) B’ = (-1 , -1)

C = (2, 2) C’ = (-1 , 2)

Explanation:

Move each coordinate to the left 3 times! You will result in the prime coordinates of the letters!