Question

If molten sodium chloride is split by electrolysis, which reaction occurs at the anode?

2Cl2 (g) →2Cl− (l) + 2e−


2Cl− (l) →Cl2 (g) + 2e−


2Na (l) →2Na+ (l) + 2e−


2Na+ (l) + 2e−→2Na (l)

Answer 1

2Cl- (l) → Cl2 (g) + 2e-

Answer 2

Answer:
`2Cl^-(l)\rightarrow 2e^-+Cl_2(g)`

Step-by-step explanation:

Electrolysis of a subastance is breaking it into its constituents by the action of electrical current.

In the electrolysis of molten sodium chloride, sodium metal is produced at the cathode which is a negative electrode and chlorine gas produces as the anode which is a positive electrode.

`2NaCl(l)\rightarrow 2Na^++2Cl^-`

At anode :
`2Cl^-(l)\rightarrow 2e^-+Cl_2(g)`

At cathode :
`2Na^+(l)+2e^-\rightarrow 2Na(l)`