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How much does 0.0273 moles of Na2O weigh

User Nate Hitze
by
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1 Answer

2 votes

Answer:

1.69 g Na₂O

General Formulas and Concepts:

Chemistry - Atomic Structure

  • Reading a Periodic Table
  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

0.0273 mol Na₂O

Step 2: Identify Conversions

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Na₂O - 2(22.99) + 16.00 = 61.98 g/mol

Step 3: Convert


0.0273 \ mol \ Na_2O((61.98 \ g \ Na_2O)/(1 \ mol \ Na_2O) ) = 1.69205 g Na₂O

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.69205 g Na₂O ≈ 1.69 g Na₂O

User Nyambaa
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