194k views
10 votes
Find the equation of a circle with a center at (1, 4) where a point on the circle is (4, 8). ( x - 1) 2 + ( y - 4) 2 = 25 ( x - 4) 2 + ( y - 1) 2 = 25 ( x - 1) 2 + ( y - 4) 2 = 5

User Manolete
by
5.6k points

1 Answer

6 votes

Answer:

(x-1)^4 + (y-4)^2 = 25

Explanation:

Center at 1,4 means the circle is of the form:

(x-1)^4 + (y-4)^2 = r^2

Find r^2 using distance formula from center to the given point

r ^2 = ( 8-4)^2 + (4-1)^2

r^2 = 16 +9 = 25

so you answer is (x-4)^4 + (y-8)^2 = 25

User Mujahid
by
6.0k points