Question

NEED HELP ASAP! ITS IN THE IMAGE BELOW.

i’ve done the graph which is part a and b but i need help in part c and d, help will be appreciated!

Answer 1

(a) see below

(b) see attached

(c) (15, 180) is not on the line

(d) a = -40

Explanation:

Given equation:

`y = 10x+20`

Part (a)

To complete the table of values, simply substitute each value of x into the given equation:

`x=-3 \implies y=10(-3)+20=-10`

`x=-1 \implies y=10(-1)+20=10`

`x=0 \implies y=10(0)+20=20`

`x=1 \implies y=10(1)+20=30`

`x=3 \implies y=10(3)+20=50`

`\large \begin{array} c \cline{1-8} x & -3 & -2 & -1 & 0 & 1 & 2 & 3\\\cline{1-8} y & -10 & 0 & 10 & 20 & 30 & 40 & 50\\ \cline{1-8} \end{array}`

Part (b)

Plot 2 points from the table and draw a straight line through them.

Part (c)

To determine if (15, 180) is on the line, substitute x = 15 into the given equation of the line:

`\begin{aligned} x=15 \implies y & =10(15)+20\\& = 150 + 20\\& = 170\end{aligned}`

Therefore (15, 180) is not on the line

Part (d)

If (-6, a) is on the line, substitute x = -6 and y = a into the equation and solve for a:

`\begin{aligned} y & = 10x+20\\\implies a & = 10(-6)+20\\a & = -60 + 20\\a & = -40\end{aligned}`

Therefore, a = -40