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A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?

User Dhulihan
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1 Answer

4 votes

Answer:

No it will not make to the top of the hill

Step-by-step explanation:

From the question we are told that

The velocity is
v = 4 \ m/s

The height of the hill is
h = 1 \ m

Generally from the law of energy conservation we have that

The kinetic energy of the pluck at the level position = The potential energy of the pluck at the maximum height the pluck can get to

So


(1)/(2) * m * v^2 = m * g * h_(max)

=>
(1)/(2) * v^2 = g * h_(max)

=>
h_(max) = (0.5 * v^2)/(g)

=>
h_(max) = 0.8163 \ m

Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill

User YiFeng
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