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A student is standing 20 feet away from the base of a tree. He looks to the top of the tree at a 50 degree angle of elevation. His eyes are 5 feet above the ground. Using cos 50= .64, what is the height of the tree to the nearest foot?

User Mmdanziger
by
5.0k points

2 Answers

3 votes

Answer:

24 feet

Explanation:

EZ

User Gabe Hollombe
by
3.9k points
3 votes

Answer:

23.84 feet

Explanation:

Solving this question above, we using Trigonometric function tangent = Opposite/Adjacent

Opposite side + h = Height of the tree

We are told that:

A student is standing 20 feet away from the base of a tree. He looks to the top of the tree at a 50 degree angle of elevation. His eyes are 5 feet above the ground.

20 feet = Adjacent side = Distance form the tree

tan 50 = (h+5)/20

Cross Multiply

h + 5 = 20 × tan50

h = 20tan50 - 5

h= 18.835071852

h =18.84

Therefore the height of the tree is calculated as:

18.84+5 feet

=23.84 feet

User Nirali Kavar
by
4.1k points