Question

Mr. T's Tea store has two kinds of tea. Tea A costs $9 per pound and Tea B cost $6 per pound. How many pounds of each should be combined to obtain 150 pounds of tea worth $8 per pound? ​

Answer 1

y=447.3 pounds

x= 297.3 pounds

Explanation:

Step one:

given data

Tea A costs $9 per pound and

Tea B cost $6 per pound.

let the number of pounds of Tea A be x

and for Tea B be y pounds

The total cost of the mixture = $8 per pound

hence

9x+6y=8---------1

The total weight of the mixture

150 pounds

x+y=150-----------2

Step two:

9x+6y=8---------1

x+y=150---------2

from eqn 2 x=150-y

put x= 150-y in eqn 1

9(150-y)+6y=8---------1

1350-9y+6y=8

1350-8=9y-6y

1342=3y

divide both sides by 3

y= 1342/3

y=447.3 pounds

put y= 447.3 in eqn 2

x+447.3= 150

x= 150-446=7.3

x= -297.3

x= 297.3 pounds