Question

PLS HELP I DONT KNOWWW!!

Answer 1

This can be solved using the gradient-intercept formula:

y = mx + c

where,
m is the gradient, and
c is the y-intercept (where the line crosses the y-axis)

Gradient can be calculated using the following formula, or rise/run:

m = (y2 - y1)/(x2 - x1)
= (-1 - - 2)/(4 - 0)
= 1/4

Therefore, using the gradient-intercept form:
y = mx + c
y = (1/4)x + (-2) (-2 is the point where the line crosses the y-axis)

Therefore, y = (1/4)x - 2 or Option C is the answer

Answer 2

3rd option

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (0, - 2) and (x₂, y₂ ) = (4, - 1) ← 2 points on the line

m =
`(-1-(-2))/(4-0)` =
`(-1+2)/(4)` =
`(1)/(4)`

the line crosses the y- axis at (0, - 2 ) ⇒ c = - 2

y =
`(1)/(4)` x - 2 ← equation of line