Answer:
104.7 in^3
Explanation:
Step one:
given data
The ball has a radius of 5 inches and
the cylinder has a height of 8 inches
Step two:
The volume of the cylinder
![v= \pi r^2 h](https://img.qammunity.org/2021/formulas/mathematics/high-school/cxfnk4r0e2x7ie8yptati14mjc0vpah0j5.png)
substitute our data
![v= 3.142*5^2*8\\\\v=628.4in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/66t53qr8bm5qpg5qpp1rpamllk0uc2xqhx.png)
The volume of the ball
![v=4/3 \pi r^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/8qatchwf7avcmygtpaax0l36r9a5grpr8q.png)
substitute our data
![v= 4/3 *3.142*5^3\\\\v= 523.7 in^3](https://img.qammunity.org/2021/formulas/mathematics/high-school/3oy313cnbnpksoypic1g3oje14p0h8jv47.png)
The space will have a volume of
=628.4-523.7
=104.7 in^3