Question

A population of Muscovy ducks contains 13 birds with black masks and 37 birds with red masks. Red masks are the dominant trait. What is the frequency of the black allele? What is the frequency of the red allele? What is the frequency of heterozygotes?

Answer 1

The frequency of the black allele is 25%, the frequency of the red allele is 75%, and the frequency of heterozygotes is 37.5% in the population of flowers.

Step-by-step explanation:

To determine the allele frequencies for flower color in a population, we can use the Hardy-Weinberg equation. The equation states that the square of the frequency of the dominant allele is equal to the frequency of homozygous dominant individuals, while the square of the frequency of the recessive allele is equal to the frequency of homozygous recessive individuals. Additionally, the frequency of heterozygotes can be determined by multiplying twice the frequency of the dominant allele by the frequency of the recessive allele.

In this case, we have 600 blue flowers and 200 red flowers. Since blue flower color is dominant to red flower color, the blue flowers represent the homozygous dominant (BB) and heterozygous (Bb) individuals, while the red flowers represent the homozygous recessive (bb) individuals.

Therefore, the expected allele frequencies for flower color are:

• The frequency of the black allele (b) is 200/(200+600) = 0.25 or 25%.
• The frequency of the red allele (B) is 1 - 0.25 = 0.75 or 75%.
• The frequency of heterozygotes (Bb) is 2 * 0.25 * 0.75 = 0.375 or 37.5%.

Answer 2

The frequency of the black allele is 25%, the frequency of the red allele is 75%, and the frequency of heterozygotes is 37.5% in the population of flowers.

Step-by-step explanation:

To determine the allele frequencies for flower color in a population, we can use the Hardy-Weinberg equation. The equation states that the square of the frequency of the dominant allele is equal to the frequency of homozygous dominant individuals, while the square of the frequency of the recessive allele is equal to the frequency of homozygous recessive individuals. Additionally, the frequency of heterozygotes can be determined by multiplying twice the frequency of the dominant allele by the frequency of the recessive allele.

In this case, we have 600 blue flowers and 200 red flowers. Since blue flower color is dominant to red flower color, the blue flowers represent the homozygous dominant (BB) and heterozygous (Bb) individuals, while the red flowers represent the homozygous recessive (bb) individuals.

Therefore, the expected allele frequencies for flower color are:

• The frequency of the black allele (b) is 200/(200+600) = 0.25 or 25%.
• The frequency of the red allele (B) is 1 - 0.25 = 0.75 or 75%.
• The frequency of heterozygotes (Bb) is 2 * 0.25 * 0.75 = 0.375 or 37.5%.

Answer 3

Answer: Black allele has frequency of 0.14.

Red allele has frequency of 0.86.

The frequency of heterozygotes is 0.241

Step-by-step explanation: Hardy-Weinberg model states the frequency of alleles in a population will stay in equilibrium as long as there are external influences. It is also used to determine alleles frequencies using the following equations:

`p+q=1`

`p^(2)+2pq+q^(2)=1`

p represents frequency of dominant allele;

q represents frequency of recessive allele;

2pq is frequency of heterozygotes;

For the frequency of red allele, which is dominant, we can use:

`p^(2)=(37)/(13+37)`

`p^(2)=(37)/(50)`

`p^(2)=0.74`

`p=√(0.74)`

p = 0.86

For the black allele:

`p+q=1`

`q=1-p`

`q=1-0.86`

q = 0.14

Frequency of heterozygotes is

2pq = 2(0.86)(0.14)

2pq = 0.241

Frequencies for a population of Muscovy ducks are 0.86 for red allele, 0.14 for black allele and 0.241 for heterozygote.