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Divya wants to rent a car to drive for the weekend. The rental company has a special that allows her to rent it for $200 for the weekend, plus $0.07 per mile. Divya only has $230. Write an inequality, solve, and determine her limitations when renting.

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Answer:


200 + 0.07m \leq 230

A maximum of
\approx 428 miles is the distance what Divya can travel.

Explanation:

Given that:

Rent to be paid for the car in the weekend = $200

Charges to be paid per mile = $0.07

Total money available with Divya = $230

To find:

The inequality as per her limitations and solution to the problem.

Solution:

Let the number of miles for which Divya can drive =
m miles

Charges for one mile = $0.07

Charges for
m miles = $0.07
m

Total charges for renting and
m miles = Rental charges + Operational charges

Total charges for renting and
m miles = $200 + $0.07
m

These are charges must be lesser than equal to the amount of money available with Divya.

Therefore, we can write:


200 + 0.07m \leq 230

Subtracting 200 from both the sides:


0.07m \leq 30

Dividing both sides with 0.07:


m \leq (30)/(0.07)\\m\leq 428.6

Therefore, a maximum of
\approx 428 miles is the distance what Divya can travel.

User Corey Ross
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