Question

Divya wants to rent a car to drive for the weekend. The rental company has a special that allows her to rent it for $200 for the weekend, plus $0.07 per mile. Divya only has $230. Write an inequality, solve, and determine her limitations when renting.

Answer 1

`200 + 0.07m \leq 230`

A maximum of
`\approx` 428 miles is the distance what Divya can travel.

Explanation:

Given that:

Rent to be paid for the car in the weekend = $200

Charges to be paid per mile = $0.07

Total money available with Divya = $230

To find:

The inequality as per her limitations and solution to the problem.

Solution:

Let the number of miles for which Divya can drive =
`m` miles

Charges for one mile = $0.07

Charges for
`m` miles = $0.07
`m`

Total charges for renting and
`m` miles = Rental charges + Operational charges

Total charges for renting and
`m` miles = $200 + $0.07
`m`

These are charges must be lesser than equal to the amount of money available with Divya.

Therefore, we can write:

`200 + 0.07m \leq 230`

Subtracting 200 from both the sides:

`0.07m \leq 30`

Dividing both sides with 0.07:

`m \leq (30)/(0.07)\\m\leq 428.6`

Therefore, a maximum of
`\approx` 428 miles is the distance what Divya can travel.