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![\text{\textbf{Hello!} In this question, we are trying to figure out the \underline{equation} of the line}\\\text{with the given information.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/wx2qqnydm249m190jxmguyd34kelzkybfb.png)
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![\textbf{Explanation:}\\\quad{}\\\text{In the question, we were given our \emph{slope} (gradient) and a \emph{point}. This will help}\\\text{us solve our problem.}\quad{}\\\\\text{Slope: 2 }\\\\\text{Point: (1, 4)}\\\quad{}\\\text{In order to find the equation, we will be using the \underline{point-slope formula:}}\\\quad{}\\y - y1 = m(x - x1)\\\quad{}\\\text{With this equation, we would plug in our given values to its}\\\text{correct variable and solve.}](https://img.qammunity.org/2023/formulas/mathematics/high-school/275yqxa0hq9qk989yrt3ahskcfmq83z1e5.png)
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![\textbf{Solve:}\\\\\text{Use the point-slope formula to solve.}\\\\y - y1 = m(x - x1)\quad{}\\\\\text{Plug in 2 to m, 1 to x1, 4 to y1 and then solve.}\\\\y - 4 = 2(x - 1)\\\\\text{Use the \underline{distributive property} to distribute the 2.}\\\\y - 4 = 2x - 2\\\\\text{Add 4 to both sides to cancel the 4 on the left and move the remainder}\\\text{to the right side of the equal sign.}\\\\y = 2x + 2\\\\\text{Since we can't simplify any further, our answer is: \fbox{y = 2x + 2}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/5vwtrx5bkqvcpgtw8v92fz0gnfd55zzc7u.png)
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![\textbf{Answer:}\\\\\text{Therefore, the equation of the line (our final answer) would be \fbox{y = 2x + 2}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/r894pl3yz24khk6bamp1gfcq1kif2l6d7y.png)
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