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What is the final temperature (in °C) of 750.1 g of water (specific heat = 4.184 J/g・°C) at 24.20°C that absorbed 950.0 J of heat?

User Kaslico
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2 Answers

8 votes

Answer:

... r ra to to isis bty is hdig

User Kamlendra Sharma
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8 votes

Q=mcΔt

Δt=Q/mc

t-24.2 = 950/(750.1 x 4.184)

t=24.5 °c

User Enzotib
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