Question

g If the quantity of helium in a weather balloon in increased by a factor of 5 at constant temperature and pressure, by how much does the volume of the balloon change? Decrease by 2 times Increase by 5 times Decrease by 5 times Increase by 2 times

Answer 1

Increase by 5 times

Explanation:

Given that from the ideal gas law;

PV = nRT

P= pressure

V= volume

n= number of moles

R= gas constant

T = temperature

It the follows that;

V= nRT/P

When the number of moles (quantity of helium) is increased by a factor of 5 while temperature and pressure remain constant, we can write;

PV = 5nRT

V = 5nRT/P

Hence the volume increases by a factor of 5.