Answer:
The magnitude of the frictional force is 50 newtons.
Step-by-step explanation:
The frictional force can be found as follows:
![\Sigma F = ma](https://img.qammunity.org/2021/formulas/physics/high-school/k3684qbd2gfug3binyiatq4993hvwd7dku.png)
![F - F_(\mu) = ma](https://img.qammunity.org/2021/formulas/physics/college/nvkuhgcnoxie86irwg4spnllt3wqfq3q0h.png)
Where:
F: is the applied force = 50 N
: is the frictional force
m: is the box's mass
a: is the acceleration
Since the box is pulled at a constant velocity, a = 0, so:
![F - F_(\mu) = 0](https://img.qammunity.org/2021/formulas/physics/college/28kcjvv1kryfejlrze9mqmitpjpczt2tpi.png)
![F = F_(\mu) = 50 N](https://img.qammunity.org/2021/formulas/physics/college/hnkcsr9ynt0d0lhnv1omz8gcuk2aegxgx2.png)
Therefore, the magnitude of the frictional force is equal to the applied force, that is to say, 50 newtons.
I hope it helps you!