Answer:
- The resistance of the filament is 333.33 ohms
Step-by-step explanation:
Given;
output power of the incandescent lightbulb , P = 120 W
input voltage, V = 200 V
The resistance of the filament is calculated as;
![P = (V^2)/(R)](https://img.qammunity.org/2021/formulas/physics/middle-school/hkvkzxb1fu845dne22xvyraglrwqgg4qua.png)
Where;
R is the resistance of the filament
![R = (V^2)/(P) \\\\R = (200^2)/(120) \\\\R = 333.33 \ ohms](https://img.qammunity.org/2021/formulas/physics/college/k51e4lzok97i7qfs9vfuqtkq0d6dw5e77r.png)
The rms current is given as;
![P = I_(rms) V_(rms)\\\\I_(rms) = (P)/(V_(rms)) \\\\I_(rms) =(120)/(200)\\\\ I_(rms) = 0.6 \ A](https://img.qammunity.org/2021/formulas/physics/college/dtlauqum3dqzh8v655g44n3vo9g1kb29a6.png)