Question

Henry made himself a sandwich that was StartFraction 11 Over 12 EndFraction of a foot long. He put pepperoni on Three-fourths of his sandwich. What length of the sandwich did not have pepperoni on it?

Answer 1

11/48

Explanation:

i did this in 6th grade 6 years ago

Answer 2

`\bold{(11)/(48)\ ft}`

Explanation:

Given that:

Length of sandwich =
`(11)/(12)` of a foot =
`(11)/(12)` ft

Portion of sandwich on which there is pepperoni =
`(3)/(4)` of the total length of sandwich

Portion of sandwich on which there is pepperoni =
`(3)/(4)`
`* (11)/(12)` ft

To find:

The length of sandwich which does not have the pepperoni on it?

Solution:

First of all, let us find the length which has the pepperoni on it.

Length of sandwich on which there is pepperoni =
`(3)/(4)`
`* (11)/(12)` ft =
`(33)/(48)` ft

Length of sandwich on which there is no pepperoni can be found by subtracting the length on which there is pepperoni from the total length of sandwich.

Therefore, the answer is:

`(11)/(12) - (33)/(48) = (44-33)/(48) = \bold{(11)/(48)\ ft}`