Question

A resistor utilized in a critical electronic component is required to have a resistance of 45 ohms /- 0.32 ohms. The current manufacturer of this resistor has found that its manufacturing process produces a mean value of 50 ohms and has a standard deviation of 0.16 ohms. What would be the C P of this process

Answer 1

The value is
`CP = 0.667`

Explanation:

From the question we are told that

The resistance is
`R = 45 \pm 0.32\ \Omega`

The mean is
`\mu = 50 \Omega`

The standard deviation is
`\sigma = 0.16 \Omega`

Generally the upper limit of the resistance specified in the question(i.e upper specification limit (USL )) is

`USL = 45 + 0.32 = 45.32 \ \Omega`

Generally the lower limit of the resistance specified in the question(i.e lower specification limit (USL )) is

`LSL = 45 - 0.32 = 44.68 \ \Omega`

Generally the CP of the process of manufacturing the resistor is mathematically represented as

`C P = ( USL - LSL )/( 6 * \sigma )`

=>
`CP = (45.32 - 44.68 )/(6 * 0.16)`

=>
`CP = (0.64 )/(0.96)`

=>
`CP = 0.667`