220k views
2 votes
A W18 X 119 is used as a compression member with one end fixed and the other end pinned. The length is 12 feet. What is the design compressive strength of A992 steel is used

1 Answer

1 vote

Answer:

156.0 ksi

Step-by-step explanation:

The formula of compressive strength is CS = F / A

where F is the force or load while A is the cross-sectional area

Given the inertia Ag = 35.1 in^4 , which is less than 40, the steel has a short column.

E = 29000 ksi

L = 12ft

r = 2.69 in

therefore;

CS = π^2 E / (kL^2/r)^2

= π^2 29000 / (0.8 x 12^2 / 2.69)^2

= 286292.756 / 1834.4089 = 156 ksi

User James Carr
by
5.5k points