Answer:
More than 6.21 times
Explanation:
The common ratio
![r=(4)/(5)](https://img.qammunity.org/2021/formulas/mathematics/college/qv1213n8ylwn7vdyz08ezkoz3skbhvh2tg.png)
Distance of first bounce
![a_1=4* (4)/(5)=(16)/(5)](https://img.qammunity.org/2021/formulas/mathematics/college/6bxfgejtdba8l8h7i3pg4g6bmx7p2xqidh.png)
Second bounce
![a_2=ar^(n-1)=(16)/(5)((4)/(5))^(2-1)\\\Rightarrow a_2=(16)/(5)((4)/(5))](https://img.qammunity.org/2021/formulas/mathematics/college/86hxkuwoqk5motw0j7okegiij6kpxcl5j6.png)
n bounce
![a_n=ar^(n-1)\\\Rightarrow a_n=(16)/(5)((4)/(5))^(n-1)](https://img.qammunity.org/2021/formulas/mathematics/college/fb6frv8hxvbtsw7ahh11n3764cyc6v747v.png)
Now the nth bounce will be less than 1 feet
![(16)/(5)((4)/(5))^(n-1)<1\\\Rightarrow ((4)/(5))^(n-1)<(5)/(16)](https://img.qammunity.org/2021/formulas/mathematics/college/zy3dqtnu6uzt55q3pde6xza3bzsabjrkcc.png)
Applying logarithms on both sides we get
![(n-1)\ln (4)/(5)<\ln(5)/(16)\\\Rightarrow n>(\ln(5)/(16))/(\ln (4)/(5))+1](https://img.qammunity.org/2021/formulas/mathematics/college/u6kpgmyonrowqwnjyoz9hdktmuttb1w31o.png)
The inequality changes as both
and
are negative numbers.
So,
![n>6.21](https://img.qammunity.org/2021/formulas/mathematics/college/9m4uy8t4642da9nt38jt2qoes89qf16g2q.png)
Hence, the number of bounces is more than 6.21 times.