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What is the force on a 1000 kg elevator that is free falling at 9.8 m/s/s?
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What is the force on a 1000 kg elevator that is free falling at 9.8 m/s/s?

User Moog
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3 votes

Answer:

Step-by-step explanation:

Force = (mass) · (acceleration)

= (1,000 kg) · (9.8 m/s²)

= 9,800 newtons

User Masuri
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