Question

Write the equation for the line that is parallel to y=2/3x-5 and goes through the point (-12/2)

Answer 1

So this is just an easy substitution problem. We want to start off writing the question y= 2/3x-5 and then off to the side writing (-12, 2) labeling -12 as X and 1 as Y. Then we want to pick whether we want to solve for X or y first (it doesn’t matter) I chose to solve for X first but to solve for x you need to substitute 2 in from the given pair that was given to you. You replace Y in the original equation with 2 and then solve the equation as normal, add like pairs (add five to each side, we’re trying to get x alone), then you have 7= 2/3x, divide 2/3 on each side and you’ll get X= 10.5. So now we have to solve for Y, to solve for Y we need to replace the X in the original equation (y= 2/3x- 5) for -12 in the given pair that was given to you. So you’ll have Y= 2/3(-12) -5, now filling pemdas we’ll multiply 2/3 and -12 and get -8 then we subtract 5 from -8 and we get Y= -13. So our final answer should always be in an ordered pair, we should have (10.5, -13) as the final answer.

Answer 2

I put the equation into Point-Slope Form and got:

y - 2 = 2/3(x + (-12))

Distribute the 3 to the numbers on the left:

3y - 6 = 2(x - 12)

Multiply the Parenthesis by 2:

3y - 6 = 2x - 24

Add 6 to the right side:

3y = 2x - 18

Divide both sides by 3:

y = 2/3x - 6 is the answer :)