Answer:
Jenny James would need to have a score of 97 out of 100 points in order to have an average of 90.
Explanation:
Given that:
Scores of four tests
78, 89, 90 and 96
Let,
x be the score on fifth test.
Average is the sum of quantities divided by total number of quantities.
Average = 90
Average =
![(Sum\ of\ scores)/(No.\ of scores)](https://img.qammunity.org/2021/formulas/mathematics/high-school/t8shsdtv6n8poouvouc9p9l33jp9einu5x.png)
Putting the values in the formula;
![90=(78+89+90+96+x)/(5)\\90=(353+x)/(5)\\90*5=353+x\\450=353+x\\450-353=x\\x=97](https://img.qammunity.org/2021/formulas/mathematics/high-school/mmtgl4wnyp91d4z7l5i3es221pm6sxub9g.png)
Hence,
Jenny James would need to have a score of 97 out of 100 points in order to have an average of 90.