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What is the actual slope of a line with the points (-4, 9) and (3, -5)?

User Metadings
by
7.9k points

2 Answers

7 votes

Answer:

-2

Explanation:

slope equation: (y2-y1)/(x2-x1)

lets use (-4, 9) as x1 and y1 and (3, -5) as x2 and y2

when plugged into the equation we get (9+5)/(-4-3) which ultimately equals -2.

User Oyvindio
by
8.1k points
1 vote

Answer:

slope=∆y/∆x=9+5/-4-3=14/-7=-2

User Chirag Purohit
by
8.3k points

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