Question

A sample of gas in a balloon has an initial temperature of 42 ∘C and a volume of 1.10×103 L . If the temperature changes to 86 ∘C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas?

Answer 1

1250L or 1.25*10^3

Step-by-step explanation:

Use the combined gas law,
`(P_(1) V_(1))/(T_(1) )`=
`(P_(2)V_(2))/(T_(2) )`

Put the value for the temperature(in Kelvin) and volume, and you can just put 1 for P1 and P2 because it stays the same.

I'll assume that you meant to put 1.10*10^3L