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How many solutions does this linear system have?

y=-1/2x+4
one solution: (8, 0)
one solution: (0, 8)
no solution
infinite number of solutions

How many solutions does this linear system have? y=-1/2x+4 one solution: (8, 0) one-example-1

2 Answers

2 votes

Answer:

No solution

Explanation:

Got it right edge 2020

User Albara
by
4.9k points
0 votes

Answer:

The system of equations has no solution.

NO SOLUTION!

Explanation:

Given the system of equations


\begin{bmatrix}y=-(1)/(2)x+4\\ x+2y=-8\end{bmatrix}

Arrange equation variables for elimination


\begin{bmatrix}y+(1)/(2)x=4\\ 2y+x=-8\end{bmatrix}


\mathrm{Multiply\:}y+(1)/(2)x=4\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:2y+x=8


\begin{bmatrix}2y+x=8\\ 2y+x=-8\end{bmatrix}

subtracting equation 2y+x=8 from 2y+x = -8


2y+x=-8


-


\underline{2y+x=8}


0=-16

so the equations become


\begin{bmatrix}2y+x=8\\ 0=-16\end{bmatrix}

0 = -16 is false, therefore the system of equations has no solution.

NO SOLUTION!

The diagram is also attached below.

How many solutions does this linear system have? y=-1/2x+4 one solution: (8, 0) one-example-1
User Cedric Martens
by
5.8k points