Question

A 1405 kg car is accelerating at

1.77 m/s? Its engine creates a forward
force of 3150 N, and air resistance
creates a backward force. What is
the magnitude (+) of the force of
air resistance or the car?
(Unit = N)

Answer 1

fair = 663.15 [N]

Step-by-step explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F = forces applied [N]

m = mass = 1405 [kg]

a = acceleration = 1.77 [m/s²]

In this way, we have two forces, the one that develops the engine to move the car and the resistance force of the air that opposes the movement of the car.

`3150-f_(air)=m*a\\3150-f_(air)=1405*1.77\\f_(air)=3150-2486.85\\f_(air)=663.15[N]`