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Complete the description of the slope of the line that joins the points

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negative
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Complete the description of the slope of the line that joins the points positive negative-example-1

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Answer:

The slope of the line that joins the points is negative.

i.e m = -6/5

Explanation:

Taking two points from the graph to determine the slope

  • (-3, 4)
  • (2, -2)

Finding the slope between (-3, 4),(2, -2)


\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)'


\left(x_1,\:y_1\right)=\left(-3,\:4\right),\:\left(x_2,\:y_2\right)=\left(2,\:-2\right)


m=(-2-4)/(2-\left(-3\right))


m=-(6)/(5)

Therefore, the slope of the line that joins the points is negative.

i.e m = -6/5

User Kalin Borisov
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