Question

A 6 kg bowling ball is on top of a building. It has 2,352 J of potential energy. What is the height of

the building?

Answer 1

Hello!

`\large\boxed{ h = 40m}`

Use the formula below to solve:

`\text{ Potential energy} = mgh`

Where:

m = mass of object (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height of the building (m)

We are given the potential energy, mass, and gravity, so plug in those values into the equation to solve for the height:

`2352 = 6 * 9.8 * h\\\\2352 = 58.8h\\\\2352/58.8 = 58.8h / 58.8\\\\h = 40 m`