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22 votes
22 votes
Please help 8 points each but beware if you use my points for no reason I'll report you

Please help 8 points each but beware if you use my points for no reason I'll report-example-1
User Hj David Kearns
by
3.4k points

2 Answers

15 votes
15 votes

Explanation -:

In this question we are provided with the radius of a sphere. We are asked to calculate the volume of the sphere.


\large \: \star\small\boxed{ \rm{ Volume_((sphere)) = (4)/(3) × π × r³}}

Where,

  • r stand for radius.
  • Assuming π as 3.


\small\sf{ Volume_((sphere)) = (4)/(3) × 3 × 2³}


\rightarrow \small\sf{ Volume_((sphere)) = \frac{4}{ \cancel{3}} × \cancel {3} × 8}


\rightarrow \small\sf{ Volume_((sphere)) = 4 * 8 = 32}


\bull \: \small \underline{ \boxed{\sf{ Volume_((sphere)) = 32 {cm}^(3) }}}

User Quicker
by
3.3k points
24 votes
24 votes

Answer:

V = 32

Explanation:

Comment

I think you should try this one yourself after I post my answer. Estimation is a very valuable tool -- the more you use it, the handier it gets.

Formulas

pi = 3

V = 4/3 * pi * r^3

Givens

r = 2

pi = 3

Solution

V = 4/3 * pi * r^3 Substitute values for symbols

V = 4/3 * 3 * 2^3 Cancel the 3s

V = 4 * 2^3 Expand the 2s

V = 4 * 2 * 2 * 2 Find V

V = 32

User Andrew Russell
by
2.6k points