Answer:
3.91 mmHg
Step-by-step explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 120 L
Initial pressure (P₁) = 1.5 mmHg
Initial temperature (T₁) = 10 °C
Final volume (V₂) = 50 L
Final temperature (T₂) = 34 °C
Final pressure (P₂) =?
Next, we shall convert 10 °C and 34 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 10 °C
Initial temperature (T₁) = 10 °C + 273
Initial temperature (T₁) = 283 K
Final temperature (T₂) = 34 °C
Final temperature (T₂) = 34 °C + 273
Final temperature (T₂) = 307 K
Finally, we shall determine final pressure of the gas as follow:
Initial volume (V₁) = 120 L
Initial pressure (P₁) = 1.5 mmHg
Initial temperature (T₁) = 283 K
Final volume (V₂) = 50 L
Final temperature (T₂) = 307 K
Final pressure (P₂) =?
P₁V₁/T₁ = P₂V₂/T₂
1.5 × 120/283 = P₂ × 50 / 307
Cross multiply
P₂ × 50 × 283 = 1.5 × 120 × 307
P₂ × 14150 = 55260
Divide both side by 14150
P₂ = 55260 / 14150
P₂ = 3.91 mmHg
Thus, the new pressure of the gas is 3.91 mmHg