Question

Evaluate the following function for (3, -1):
f(x, y) = 2x – 3y + xy^2

Answer 1

In (3,-1) the first number is x and the second number is y.

Replace x and y in the equation and solve:

2x - 3y + xy^2 = 2(3) -3(-1) + (3)(-1)^2

Simplify:

6 + 3 +3 = 12

The answer is 12

Answer 2

f(3, -1) = 12

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Function Notation

Explanation:

Step 1: Define

f(x, y) = 2x - 3y + xy²

(3, -1) is x =3 and y = -1

Step 2: Evaluate

1. Substitute: f(3, -1) = 2(3) - 3(-1) + 3(-1)²
2. Exponents: f(3, -1) = 2(3) - 3(-1) + 3(1)
3. Multiply: f(3, -1) = 6 + 3 + 3
4. Add: f(3, -1) = 9 + 3
5. Add: f(3, -1) = 12