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Evaluate h(x)=-2x+9 when x=-2,0 and 5

User Kcpr
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1 Answer

7 votes

Answer:

h(-2) = 13

h(0) = 9

h(5) = -1

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Explanation:

Step 1: Define

h(x) = -2x + 9

x = -2

x = 0

x = 5

Step 2: Evaluate

x = -2

  1. Substitute in x: h(-2) = -2(-2) + 9
  2. Multiply: h(-2) = 4 + 9
  3. Add: h(-2) = 13

x = 0

  1. Substitute in x: h(0) = -2(0) + 9
  2. Multiply: h(0) = 0 + 9
  3. Add: h(0) = 9

x = 5

  1. Substitute in x: h(5) = -2(5) + 9
  2. Multiply: h(5) = -10 + 9
  3. Add: h(5) = -1
User Michael Mitch
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