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Find the second and fifth terms of each sequence. A(n) = 22 + (n – 1)11

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Answer:

A(2) = 33

A(5) = 77

Explanation:

n is the counter of the terms.

A(n) is the nth term.

A(1) is the first term.

A(2) is the second term.

etc

To find the 2nd term, let n = 2. Then you have

A(2) = 22 + (2 - 1)11

A(2) = 22 + (1)11

A(2) = 22 + 11

A(2) = 33

To find the 5th term, let n = 5. Then you have

A(5) = 22 + (5 - 1)11

A(5) = 22 + (5)11

A(5) = 22 + 55

A(5) = 77

Answer:

A(2) = 33

A(5) = 77

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