Question

Let g(x)=4x and h(x)=x^2-3. Find (g o h)(0)

Answer 1

-12

Explanation:

g(x) = 4x

h(x) = x^2 - 3

(g o h)(x) = g(h(x)) = g(x^2 - 3) = 4(x^2 - 3) = 4x^2 - 12

(g o h)(0) = 4(0)^2 - 12 = 0 - 12 = -12

Answer 2

(goh)(x) means inserting the value of h(x) in g(x) so:

(goh)(x) = 4(x^2 - 3) = 4x^2 - 12

Now to find (goh)(0) you can substitute 0 to the x:

(goh)(0) = 4*0 - 12 = -12