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Solve in order of operation
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Solve in order of operation Thanks-example-1

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Answer:

b) 31 and c) 11

Explanation:

IMPORTANT: Order of operations is PEMDAS (Parentheses, Exponents, Multiplication/Division, Addition/SUbtraction).

B) Solve inside the parentheses first.

1. 2^3 - 6 = (2*2*2) - 6 = 2.

2. Now the equation looks like 3 + 7 (2)^2, Next we need to do exponents.

3. 2 to the power of 2 is 4, leaving you with 3+7(4)

4. Now multiply 7*4, which is 28 then add 3 to it.

So B) would ultimately be 31.

C) As we did in equation B, we start with parentheses.

1. (6/3) we can just simplify this to 2, so those parentheses are out of the way.

2. Now we need to do exponents, (-3)^2. This is the same as -3 * -3. This would equal 9.

3. So far the equation looks like 4 + 9 - 2 / 2.

4. Next would be to solve any multiplication/division problems we have. We can see from step 3 that we have a -2 divided by a positive 2. This would give us -1.

5. Now the equation looks like 4 + 9 - 2. Now you can just working from left to right.

So C) would solve to 11

Please let me know if I made any errors, good luck!

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