30.0k views
3 votes
Solve in order of operation
Thanks

Solve in order of operation Thanks-example-1

1 Answer

3 votes

Answer:

b) 31 and c) 11

Explanation:

IMPORTANT: Order of operations is PEMDAS (Parentheses, Exponents, Multiplication/Division, Addition/SUbtraction).

B) Solve inside the parentheses first.

1. 2^3 - 6 = (2*2*2) - 6 = 2.

2. Now the equation looks like 3 + 7 (2)^2, Next we need to do exponents.

3. 2 to the power of 2 is 4, leaving you with 3+7(4)

4. Now multiply 7*4, which is 28 then add 3 to it.

So B) would ultimately be 31.

C) As we did in equation B, we start with parentheses.

1. (6/3) we can just simplify this to 2, so those parentheses are out of the way.

2. Now we need to do exponents, (-3)^2. This is the same as -3 * -3. This would equal 9.

3. So far the equation looks like 4 + 9 - 2 / 2.

4. Next would be to solve any multiplication/division problems we have. We can see from step 3 that we have a -2 divided by a positive 2. This would give us -1.

5. Now the equation looks like 4 + 9 - 2. Now you can just working from left to right.

So C) would solve to 11

Please let me know if I made any errors, good luck!

User Boomturn
by
7.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.