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What is log7 12+log7m-log7n?

1 Answer

3 votes

Hello!


\large\boxed{\log_(7){((12m)/(n)})}

Use the log properties to simplify:

log (a) + log (b) = log (a · b)

log (a) - log (b) = log (a ÷ b)

Therefore:


log_(7)12 + log_(7)m - log_(7)n\\\\= log_(7)(12 * m / n}\\\\log_(7){((12m)/(n)})

User Rob Lao
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