Answer: The answer is x < 5/2 and x > -5.
Explanation:
First you need to separate the inequality and keep x on one side to maintain consistency. For instance the problem-
![(5-2x)/(3) > 0\\(5-2x)/(3) < 5\\](https://img.qammunity.org/2023/formulas/mathematics/college/6jn6wpm8qe9ylzdi6d6svv3s2wb77uf2zs.png)
Now solve as normal.
*Note: When dividing a side or multiplying a side by a negative number, the sign of the inequality switches (this will be shown when I do the equation if it doesn't make since how I word it).
![5-2x > 0*3\\5-2x < 5*3](https://img.qammunity.org/2023/formulas/mathematics/college/xuox377oc00mminq42ag481oz9yo73tf07.png)
![-2x > 0-5\\-2x < 15-5](https://img.qammunity.org/2023/formulas/mathematics/college/6arwdcwlubftappxzny7emt38sxlf15fvf.png)
![x < (-5)/(-2) =x < (5)/(2) \\x > (10)/(-2) =x > -5](https://img.qammunity.org/2023/formulas/mathematics/college/jgzai7on0mgro1ybkf75jzht177eywr1zp.png)
So, x < 5/2 and x > -5.
If anything is confusing about the procedure just leave a comment, and I'll try to explain further.