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What is the molecular formula of a component whose molar mass is 88.0 and whose percent composted is 9.1

1 Answer

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The molecular formula : C₄H₈O₂

Further explanation

Maybe a compound is 54.5% carbon, 9.1% hydrogen and 36.4% oxygen,so :

mol C :


\tt (54.5)/(12)=4.54

mol H :


\tt (9.1)/(1)=9.1

mol O :


\tt (36.4)/(16)=2.28

Divide by 2.28(the smallest ratio) :

C H : O =


\tt (4.54)/(2.28)/ (9.1)/(2.28)/ (2.28)/(2.28)=2/ 4/ 1

The empirical formula : C₂H₄O

(The empirical formula)n=molecular formula

(2.12+4.1+16)n=88

(44)n=88⇒n=2

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